How to choose the specification and buy injection molding machine?
This article is mainly for introducing how to choose the specification of the injection molding machine.
1. To calculate the relevant injection amount according to the weight of the
injection molding machine
(1) when the product is made of polystyrene,
the injection amount is Wps.
Wps = (Product weight + Total weight of the
casting head system)
When the requirement of product quality is
high, the larger value of the coefficient should be applied.
(2) if the product is made of other kind of
plastics (call X plastics), according to the above method, first calculate the
theoretical injection amount of the plastics Wx:
Wx = (1.3~1.1)×(Product weight + Total weight
of the casting head system)
But Wx can not be simply used to decide the
injection amount of the machine, it must be transformed into Wps value, here is
the transforming equation:
Wps = W×1.05/vx
vx —— the specific gravity of the plastics
Eg: if a article is made of polystyrene (PE),
and the calculated weight is 175g, the casting channel system is about 20g, the
with the above equation:
Wx = 1.2×(175)+20)=234g
You can look up the specific gravity of PE – Vx =0.92
So, Wps = 234×1.05/0.92=267g
So the best choice is 10.5 ounce (200g)
injection molding machine made by our company.
2. Calculating Mold-locking force P according to the vertical projection area of the injecting product on the molding board (head board or second board):
Mold-locking force = mold-locking force constant × projection area of the product
That is, P = KPS
In the equation:
P—— Mold-locking force (t)
S—— Vertical projection area of the product on the molding board (cm2)
Kp—— Mold-locking force constant (t/cm2)
Kp values given at the following table (Table 5)
Table -Mold-locking force constant Kp (for the injection of nice product)
3. the inner space between tie-bar is decided according to the outline size of the mold
4. the opening stroke of the injecting machine should be decided according to product height. The later should be larger than the former.
— Opening stroke calculation
5. Other subsidiary factors that may need to be considered
(2) Ejector stroke, ejecting force;
(3) Process factors;
(4) The particles of plastics (including recycled materials) should be even and not be too big and long, otherwise it is very difficult to put them into the machine and the normal production may be influenced.